13. When one mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 353.0 K, 30.33 kJ of energy (heat) is absorbed and the volume change is +28.90 L. What is ΔH for this process? (1 L·atm = 101.3 J)
(A) 27.40 kJ
(B) 33.26 kJ
(C) 1.43 kJ
(D) 30.33 kJ
(E) 59.23 kJ

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