37. For the cell: 2Ag+(aq) + Zn(s) →2Ag(s)+ Zn2+(aq) E°cell = 1.56 V The value of △G'°is: (A) -150 kJ per mole of Zn (B) -602 kJ per mole of Ag (C) -301 kJ per mole of Ag (D) -301 kJ per mole of Zn

37. For the cell: 2Ag⁺(aq) + Zn(s) →2Ag(s)+ Zn²⁺(aq) E°_cell = 1.56 V The value of △G'°is:
(A) -150 kJ per mole of Zn
(B) -602 kJ per mole of Ag
(C) -301 kJ per mole of Ag
(D) -301 kJ per mole of Zn

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40. The usual form of the experimental rate law for substitution in square planar Pt(I) complexes contains two terms: Rate =k1[PtL3X] + k2[PtL3X][Y] where PtL3X is the starting complex and Y is the entering group. The reason for the two-term law is that: (A) there are competitive associative and dissociative pathways (B) there are two competing dissociative pathways (C) the solvent enters in the rate-determining step, and then two competing fast steps follow (D) the solvent competes with Y in the rate-determining step

37. For the cell: 2Ag⁺(aq) + Zn(s) →2Ag(s)+ Zn²⁺(aq) E°_cell = 1.56 V The value of △G'°is:
(A) -150 kJ per mole of Zn
(B) -602 kJ per mole of Ag
(C) -301 kJ per mole of Ag
(D) -301 kJ per mole of Zn

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37. For the cell: 2Ag+(aq) + Zn(s) →2Ag(s)+ Zn2+(aq) E°cell = 1.56 V The value of △G'°is:(A) -150 kJ per mole of Zn(B) -602 kJ per mole of Ag(C) -301 kJ per mole of Ag(D) -301 kJ per mole of Zn

詳解 (共 1 筆)

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37. For the cell: 2Ag⁺(aq) + Zn(s) →2Ag(s)+ Zn²⁺(aq) E°_cell = 1.56 V The value of △G'°is:
(A) -150 kJ per mole of Zn
(B) -602 kJ per mole of Ag
(C) -301 kJ per mole of Ag
(D) -301 kJ per mole of Zn