8. 令 $f(x) = \begin{cases} 3x^2 + a, & x < 0 \\ 4x - b, & 0 \leq x \leq 1 \\ \sqrt{x + 8}, & x > 1 \end{cases}$;若 f(x) 為到處連續的函數,則 a、b 值應為何?
(A) a = -1, b = 1
(B) a = 1, b = -1
(C) a = -1, b = 2
(D) a = 1, b = -2

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