9. Calculate the molar mass of a sample with a single molecule weighs 9.31 × 10^-23 g. (A) 56.1 g/mol (B) 6.47 × 10^41 g/mol (C) 6.02 × 10^23 g/mol (D) 9.31 × 10^-23 g/mol

19. For the equilibrium that exists in an aqueous solution of nitrous acid $(\mathrm{HNO}_2$ , a weak acid), the equilibrium constant expression is: (A) $K = \frac{[\mathrm{H}^{+}][\mathrm{NO}_{2}^{-}]}{[\mathrm{HNO}_{2}]}$ (B) $K = \frac{[\mathrm{H}^{+}][\mathrm{N}^{2+}][\mathrm{O}^{2-}]^2}{[\mathrm{HNO}_2]}$ (C) $K = [\mathrm{H}^{+}]\mathrm{[NO}_{2}^{-}]$ (D) $K = \frac{[\mathrm{H}^{+}]^{2}[\mathrm{NO}_{2}^{-}]}{[\mathrm{HNO}_{2}]}$

9. Calculate the molar mass of a sample with a single molecule weighs $$9.31 \times 10^{-23}$$ g.
(A) 56.1 g/mol
(B) $$6.47 \times 10^{41}$$ g/mol
(C) $$6.02 \times 10^{23}$$ g/mol
(D) $$9.31 \times 10^{-23}$$ g/mol

相關試題

相關試卷

9. Calculate the molar mass of a sample with a single molecule weighs $$9.31 \times 10^{-23}$$ g.(A) 56.1 g/mol(B) $$6.47 \times 10^{41}$$ g/mol(C) $$6.02 \times 10^{23}$$ g/mol(D) $$9.31 \times 10^{-23}$$ g/mol

相關試題

相關試卷

9. Calculate the molar mass of a sample with a single molecule weighs $$9.31 \times 10^{-23}$$ g.
(A) 56.1 g/mol
(B) $$6.47 \times 10^{41}$$ g/mol
(C) $$6.02 \times 10^{23}$$ g/mol
(D) $$9.31 \times 10^{-23}$$ g/mol