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織物組合與分析

輪機當值

專業知識測驗（公共管理、公共政策）

115年 - 機車駕照筆試_英文 1-50（2026/01 更新）#144924(50題)

115年 - 115 挑戰勞動知識王國中題庫_勞動權益(勞動基準科)#144895(100題)

115年 - 115 挑戰勞動知識王國中題庫_就業安全(就業安全科)#144894(35題)

115年 - 115 挑戰勞動知識王國中題庫_職業安全衛生(勞動檢查處)#144893(90題)

115年 - 115 挑戰勞動知識王國中題庫_就業安全(就業服務處)#144892(35題)

115年 - 115 挑戰勞動知識王國中題庫_勞工福利(福利促進科)#144891(90題)

115年 - 115 挑戰勞動知識王國中題庫_促進勞資和諧(勞資關係科)#144889(90題)

115年 - 115 經濟部所屬產業園區管理機構_新進約僱人員甄選試題_行政服務組_專業科目（一）：公文寫作#144885(1題)

115年 - 115 經濟部所屬產業園區管理機構_新進約僱人員甄選試題_行政服務組_專業科目（一）：英文初級#144884(10題)

115年 - 115 經濟部所屬產業園區管理機構_新進約僱人員甄選試題_行政服務組_專業科目（一）：法學緒論、民法概要（總則、物權債編租賃第二章第五節）及政府採購法#144883(30題)

複選題50. 有關輕水式核能電廠之「緊急柴油發電機」系統，下列論述那些是正確的？ (A)於收到「緊要匯流排」失去電壓訊號時啟動 (B)於收到「安全注水訊號」時啟動 (C)啟動後立即併聯至相關匯流排 (D)於啟動 2 秒鐘內，依事先設定的負載時序，依序加入負載 (E)輸出之電力為三相 4.16KV 之交流電

複選題49. 有關汽機(Steam Turbine)的描述，下列何者正確？ (A)汽機的設計，首要原則為：運轉時葉片不能發生振動 (B)蒸汽噴嘴與動葉片轉動方向之入射角愈小，所得推力愈小 (C)汽機的熱損，來自於「工作蒸汽」在汽機中無法等熵做功 (D)汽機的轉速愈高，效率一定愈高 (E)汽機的級效率(stage efficiency)計算，不包括機械損失

複選題48. PWR 核能電廠，當全功率運轉時，發生蒸汽產生器之二次側主蒸汽管斷管，若反應爐未急停，安全設備皆未動作，則一開始時，下列那些反應器的物理現象為正確？ (A)加入「正」的核反應度 (B)「緩和劑核反應溫度係數」之正、負號值改變 (C)「燃料核反應溫度係數」之正、負號值改變 (D)不致於發生功率震盪 (E)分裂產物之中子吸收毒物濃度會先增加

六、企業有計畫性承擔(Planned Retention)之危險管理措施，較具體者有(一)自己保險(Self-Insurance)(二)專屬保險(Captive Insurance)及(三)自負額(Deductible)保險三種，試申論採行「自己保險」與「專屬保險」兩種措施時之成立要件及其優缺點。(20分)

五、危險管理為達成近代企業管理中安全保障功能的主要方法之一，已成為企業管理不可或缺之一環，試就危險管理實施之步驟(即危險管理之程序)分別論述之。(20分)

四、企業利用統計數量方法來衡量危險(Risk Measurement)之目的有二，試說明之。(10分)

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講師：陳耘得

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E1C514

描述：中正預校資料處理員

歷屆試題

描述：歷屆國文

歷屆試題

描述：歷屆國文

10 依中央政府普通公務單位會計制度之一致規定，在政府機關之固定資產會計科目中，下列何者不 設置累計折舊科目？ (A)土地改良物 (B)房屋建築及設備 (C)租賃資產 (D)購建中固定資產

31. 期末依整學期技能、體適能、學習態度與表現給予總成績，較接近哪一評量概念？ (A)Assessment of Learning (B)Assessment for Learning (C)Assessment as Learning (D)Diagnostic Assessment

32. 社會情緒學習(SEL)的核心能力中，不包括下列何者？ (A)自我覺察 (B)自我管理 (C)自我監控 (D)社會覺察

15. An auditor desired to test credit approval on 10,000 sales invoices processed during the year. The auditor designed a statistical sample that would provide 1% risk of assessing control risk too low (99% confidence) that not more than 7% of the sales invoices lacked approval. The auditor estimated from previous experience that about 2.5% of the sales invoices lacked approval. A sample of 200 invoices was examined and 7 of them were lacking approval. The auditor then determined the upper deviation rate to be 8%. In the evaluation of this sample, the auditor decided to increase the level of the preliminary assessment of control risk because the: (A) Tolerable rate (7%) was less than the upper deviation rate (8%). (B) Expected deviation rate (7%) was more than the percentage of errors in the sample (3.5%). (C) Upper deviation rate (8%) was more than the percentage of errors in the sample (3.5%). (D) Expected deviation rate (2.5%) was less than the tolerable rate (7%).

16. In a MUS sample with a sampling interval of $10,000, an auditor discover that a selected accounts receivable with a recorded amount of $ 20,000 had am audit value of $16,000. If this is the only error discovered by the auditor, the projected error of the sample would be (A) $1,000 (B) $2,000 (C) $4,000 (D) $5,000

5. (20%) In the following, you should use uppercase letters to denote matrices and lowercase letters with subscripts to denote their entries. For example, if M is a matrix, then $m_{ij}$ denotes its (i,j)-entry. Use lowercase letters with an arrow to denote column vectors of a matrix. For example, $\vec{m}_i$ denotes the i-th column vector of the matrix M. In your proofs, use the following definitions as needed. Definition (Equality of matrices): Matrices A and B are equal if they have the same size and have equal corresponding entries $a_{ij} = b_{ij}$ for all (i,j). Definition (Matrix transpose): The transpose of an $m \times n$ matrix A is the $n \times m$ matrix denoted by $A^T$ whose (i,j)-entry is the (j,i)-entry of A. Definition (Linear combination): A linear combination of vectors $\vec{u}_1, \vec{u}_2, ..., \vec{u}_k$ is a vector of the form $c_1\vec{u}_1 + c_2\vec{u}_2 + \cdots + c_k\vec{u}_k$, where $c_1, c_2, ..., c_k$ are scalars. Definition (Standard vectors): $$\vec{e}_1 = \begin{bmatrix} 1 \\ 0 \\ \vdots \\ 0 \end{bmatrix}, \vec{e}_2 = \begin{bmatrix} 0 \\ 1 \\ \vdots \\ 0 \end{bmatrix}, ..., \vec{e}_n = \begin{bmatrix} 0 \\ 0 \\ \vdots \\ 1 \end{bmatrix}$$ Now let A denote a $m \times n$ matrix. Prove that $(A^T)^T = A$ and $A\vec{e}_i = \vec{a}_i$ for $i = 1, ..., n.